What you have to do first is to add [tex]\frac{1}{3}[/tex] and [tex]\frac{4}{5}[/tex],
Therefore we have:
= [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex]
= ( [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex] ) / 15 (15 is the smallest number that divide both denominator also known as LCD)
= (5 x 1) + (3 x 4) / 15
= 5 + 12 / 15
= [tex]\frac{17}{15}[/tex]
Therefore, the sum of [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex] is [tex]\frac{17}{15}[/tex]
But since the question says you should determine the sum of the 2 fractions, therefore you should multiply [tex]\frac{17}{15}[/tex] by 7. Therefore you should have:
[tex]\frac{17}{15}[/tex] X 7 (7 can also be expressed as [tex]\frac{7}{1}[/tex])
= [tex]\frac{17}{15}[/tex] x [tex]\frac{7}{1}[/tex] (notably, in multiplication there is no need for the fraction to have the same denominator. You can multiply both numbers at the top together (numerator) and do same with the denominator.
= [tex]\frac{119}{15}[/tex]
= [tex]7\frac{14}{15}[/tex]
Therefore, 7 times as much as the sum of [tex]\frac{1}{3}[/tex] and [tex]\frac{4}{5}[/tex] is [tex]7\frac{14}{15}[/tex]
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