Solve.

4y + 16 > –8

A.
y > –6

B.
y > –2

C.
y > 2

D.
y > 6


Sagot :

[tex]4y+16\ \textgreater \ -8 \ 4y\ \textgreater \ -8-16 \\ 4y\ \textgreater \ -24 \\ y\ \textgreater \ \frac{-24}{4} \\ y\ \textgreater \ -6 \\ \hbox{answer A}[/tex]
answer is A. y>-6
you have to subtract 16 and -8 Which gives you -24. then divide it by 4.