BlossomFlowerid
Answered

Factor completely: 2x^3 – 32x

A. 2(x + 4)(x – 4)
B. 2x(x + 4)(x – 4)
C. x(x – 4)(x – 4)
D. 2x(x – 16)

My progress so far:
2x^3 – 32x
x^3 - 16

Sagot :

Naǫid
[tex]2x^3-32x= \\ 2x(x^2-16)= \\ 2x(x^2-4^2)= \\ \boxed{2x(x+4)(x-4)} \Leftarrow \hbox{answer B}[/tex]

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