Answer:
Gas particle motion will drop as the temperature reaches 252 K
Explanation:
Initial temperature T1 = 295 K
Final temperature, T2 = 252 K
The kinetic energy of the gas particles is related to the temperature via the following equation:
[tex]KE = \frac{3}{2} kT[/tex]
where k = Boltzmann constant
Based on the above equation we can write:
[tex]\frac{KE(1)}{KE(2)} = \frac{T1}{T2} = \frac{295}{252} = 1.17[/tex]
KE(1) = 1.17KE(2)
This implies that the kinetic energy is lower at T2 and therefore the gas particles will slow down as the balloon rises.