Sagot :
The diagonal of a square is [tex]\sqrt{2}[/tex] times its side, hence its perimeter is [tex]4*24/\sqrt{2}\approx68[/tex] feet
[tex]24=a\sqrt2\\
a=\dfrac{24}{\sqrt 2}\\
a=\dfrac{24\sqrt2}{ 2}\\
a=12\sqrt2\\\\
p=4a\\
p=4\cdot12\sqrt2\\
p=48\sqrt2\approx68[/tex]
68 ft
68 ft