Sagot :
3/8 inch is three times 1/8 inch
1/4=2/8 hence it's twice 1/8 inch
The smallest is 1/8 inch
1/4=2/8 hence it's twice 1/8 inch
The smallest is 1/8 inch
Answer: The smallest button is first button of size [tex]\frac{1}{4}\ inch[/tex]
and the greatest button is the second button of size [tex]\frac{3}{8}\ inch[/tex]
Step-by-step explanation:
Since we have given that
Length of first button is given by
[tex]\frac{1}{8}\ inch[/tex]
Length of second button is given by
[tex]\frac{3}{8}\ inch[/tex]
Length of third button is given by
[tex]\frac{1}{4}\ inch[/tex]
Now, make the denominator :
L.C.M. of 8,8, and 4 is 8
So, Length of third button is given by
[tex]\frac{1}{4}\times \frac{2}{2}=\frac{2}{8}\ inch[/tex]
So, arrangement will be
[tex]\frac{1}{8},\frac{2}{8},\frac{3}{8}[/tex]
Hence, The smallest button is first button of size [tex]\frac{1}{4}\ inch[/tex]
and the greatest button is the second button of size [tex]\frac{3}{8}\ inch[/tex]