[tex]x^2-11x+14=0 \\ \\
a=1 \\ b=-11 \\ c=14 \\ b^2-4ac=(-11)^2-4 \times 1 \times 14=121-56=65 \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-11) \pm \sqrt{65}}{2 \times 1}=\frac{11 \pm \sqrt{65}}{2} \\
\boxed{x=\frac{11 - \sqrt{65}}{2} \hbox{ or } x=\frac{11+\sqrt{65}}{2}}[/tex]
