Sagot :
[tex]n+n+1+n+2=180\\
3n+3=180\\
3n=177\\
n=59\\
n+1=60\\
n+2=61[/tex]
Those numbers are 59,60,61.
Those numbers are 59,60,61.
If the integers were all the same, then each one would be 1/3 of 180 = 60.
-- Put all three 60s on the table in front of you.
-- Take ' 1 ' away from the first one and drop it on the last one.
-- Then you have 59, 60, and 61, and their sum is still 180.