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the perimeter of a rectangle is 66 cm and its width is half its length. what are the length and the width of the rectangle?

Sagot :

IGreenid
P = 2(l + w)

w = l/2

Plug in 'l/2' for 'w' in the equation with '66':

66 = 2(l + l/2)

66 = 2l + 2l/2

66 = 2l + l

66 = 3l

22 = l

So the length is 22.

Now plug this in to find the width.

66 = 2(22 + w)

66 = 44 + 2w

22 = 2w

11 = w

So the width is 11, and the length is 22.
Arnfrsid
Let's set width = w

Then length = 2w

We can set up the equation:

[tex] 2(w+ 2w) = 66[/tex]

[tex] 2(3w) = 66[/tex]

[tex] 6w = 66[/tex]

[tex] w = \frac{66}{6} = \boxed{11}[/tex]

Then we plug in:

[tex]l = 2w = 2(11) = \boxed{22}[/tex]

Hope this helps :)

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