Using the principle of conservation of mechanical energy, calculate the maximum height achieved by a 7 N ball tossed vertically upward with an initial velocity of 10 m/s.

Sagot :

Because mechanical energy is conserved, potential energy due to gravity will equal the kinetic energy of the used to throw the ball. This is represented by mgh=.5mv^2
1. Divide both sides of the equation by m to ignore mass. The new equation will be gh=.5v^2
2. Substitute values into the equation: 9.8h=(.5)(10^2)--> 9.8h=50
3. Divide 50 by 9.8 to get h=5.102m

Explanation:

Given that

The weight of a ball, [tex]W=7\ N[/tex]

Initial velocity of the ball, [tex]v=10\ m/s[/tex]

The principle of conservation of mechanical energy states that, the total energy of a system remains conserved. The mathematical form of the principle of conservation of mechanical energy is :

[tex]\dfrac{1}{2}mv^2=mgh[/tex]

Where

m is the mass of the object

v is the velocity

h is the height

Using the conservation of energy,

[tex]\dfrac{1}{2}mv^2=mgh\\\\\dfrac{1}{2}v^2=gh[/tex]

Solving for h,

[tex]h=\dfrac{v^2}{2g}[/tex]

Put all the values,

[tex]h=\dfrac{(10)^2}{2\times 9.8}\\\\h=5.10\ m[/tex]

Answer:

The maximum height achieved by the ball is [tex]5.1\ m[/tex].

Reference:

brainly.com/question/20971995