Sagot :
BD = 66
AB:BD = 3:4
⇒ AB = (3/4)∙BD
= (3/4)∙66
= 49.5
AD = AB + BD
= 115.5
AC:CD = 5:6
⇒ AC = (5/11)∙AD
= 52.5
AB:BD = 3:4
⇒ AB = (3/4)∙BD
= (3/4)∙66
= 49.5
AD = AB + BD
= 115.5
AC:CD = 5:6
⇒ AC = (5/11)∙AD
= 52.5
first find the legnt of the line then find the
so ratios are
AB:BD=3:4
AC:CD=5:6
BD=66
subsitute
AB:66=3:4
so we know that 4 units represent 66 so divide 66 by 4
66/4=16.5
so multiply by 3 to find AB
AB=3 times 16.5=49.5
66+49.5=115.5
therfor
AC+CD=115.5
5:6
5+6=11
11 units
115.5/11=1 unit
10.5
AC:CD=5:6
AC=5 units
10.5 times 5=52.5
AC=52.5
so ratios are
AB:BD=3:4
AC:CD=5:6
BD=66
subsitute
AB:66=3:4
so we know that 4 units represent 66 so divide 66 by 4
66/4=16.5
so multiply by 3 to find AB
AB=3 times 16.5=49.5
66+49.5=115.5
therfor
AC+CD=115.5
5:6
5+6=11
11 units
115.5/11=1 unit
10.5
AC:CD=5:6
AC=5 units
10.5 times 5=52.5
AC=52.5