Answer:Use A for third graders, B for fourth graders, and C for fifth graders.
33 = A + B + C
Since there are three variables, you need to come up with two other equations to substitute in.
C = 6 + A Since there are six more fifth graders than third graders.
A = B Since there is an equal amount of third and fourth graders.
Since A is in both equations, lets put each variable in terms of A.
B = A
C = 6 + A
So: A+A+A+6=33
A+A+A=27 Since you subtract six from both sides.
3A=27 Since you combine all three A's.
A=9 Since you divide both sides by three.
Therefore, since A is the number of third graders, there are 9 third graders.
Step-by-step explanation:
