Simplify:

[tex]{ e }^{ \ln { \left( B \right) } }{ \left( \frac { 1 }{ R } \right) }^{ -1 }\int { \frac { dA }{ dx } dx } \sqrt { { I }^{ 2 } } \left| -2N+N \right| { \pi }^{ \log _{ \pi }{ \left( L \right) } }\int { \frac { 1 }{ \frac { dx }{ dY } } } dx[/tex]

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Mathematics

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Simplify:

[tex]{ e }^{ \ln { \left( B \right) } }{ \left( \frac { 1 }{ R } \right) }^{ -1 }\int { \frac { dA }{ dx } dx } \sqrt { { I }^{ 2 } } \left| -2N+N \right| { \pi }^{ \log _{ \pi }{ \left( L \right) } }\int { \frac { 1 }{ \frac { dx }{ dY } } } dx[/tex]

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Konrad509id Konrad509id · Answer 1

Konrad509id Konrad509id

[tex]{ e }^{ \ln { \left( B \right) } }{ \left( \frac { 1 }{ R } \right) }^{ -1 }\int { \frac { dA }{ dx } dx } \sqrt { { I }^{ 2 } } \left| -2N+N \right| { \pi }^{ \log _{ \pi }{ \left( L \right) } }\int { \frac { 1 }{ \frac { dx }{ dY } } } dx=\\ BRAI|-N|L\int \frac{dY}{dx}\,dx=\\ BRAINLY[/tex]

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