1/2x+1/4y=6. 1/5x+1/3y=1

[tex]\frac{1}{2}x+\frac{1}{4}y=6 \ \ \ |\times 2 \\ \frac{1}{5}x+\frac{1}{3}y=1 \ \ \ |\times (-5) \\ \\ x+\frac{1}{2}y=12 \\ \underline{-x-\frac{5}{3}y=-5} \\ \frac{1}{2}y-\frac{5}{3}y=12-5 \\ \frac{3}{6}y-\frac{10}{6}y=7 \\ -\frac{7}{6}y=7 \\ y=7 \times (-\frac{6}{7}) \\ y=-6 \\ \\ x+\frac{1}{2}y=12 \\ x+\frac{1}{2} \times (-6)=12 \\ x-3=12 \\ x=12+3 \\ x=15 \\ \\ \boxed{(x,y)=(15,-6)}[/tex]

Answer Link

Анонимid Анонимid · Answer 2

1st Step:

[tex]\frac { 1 }{ 2 } x+\frac { 1 }{ 4 } y=6\\ \\ 4\left( \frac { 1 }{ 2 } x+\frac { 1 }{ 4 } y \right) =6\cdot 4\\ \\ 2x+y=24\\ \\ y=24-2x[/tex]

2nd Step:

[tex]\frac { 1 }{ 5 } x+\frac { 1 }{ 3 } y=1\\ \\ 15\left( \frac { 1 }{ 5 } x+\frac { 1 }{ 3 } y \right) =1\cdot 15[/tex]

[tex]\\ \\ 3x+5y=15\\ \\ 5y=15-3x\\ \\ 5y=3\left( 5-x \right) \\ \\ y=\frac { 3\left( 5-x \right) }{ 5 } [/tex]

3rd Step:

[tex]\frac { 3\left( 5-x \right) }{ 5 } =24-2x[/tex]

[tex]\\ \\ 5\cdot \frac { 3\left( 5-x \right) }{ 5 } =5\left( 24-2x \right) \\ \\ 3\left( 5-x \right) =120-10x[/tex]

[tex]\\ \\ 15-3x=120-10x\\ \\ -3x+10x=120-15\\ \\ 7x=105\\ \\ x=\frac { 105 }{ 7 }[/tex]

[tex]\\ \\ \therefore \quad x=15[/tex]

4th Step (When x=15):

[tex] y=24-2\left( 15 \right) \\ \\ y=24-30\\ \\ \therefore \quad y=-6[/tex]