First, let's get the perimeter of the rectangle:
[tex]P=2W+2L[/tex]
[tex]P=130m+210m[/tex]
[tex]P=340m[/tex]
Then, let's get the area of the bigger one:
[tex]A=WL[/tex]
[tex]A=65m*105m[/tex]
[tex]A=6825m^2[/tex]
Then let's try using a rectangle with a smaller ratio:
[tex]P=100m+240m[/tex]
[tex]P=340m[/tex]
Then:
[tex]A=50m*120m[/tex]
[tex]A=6000m^2[/tex]
If you used a square:
[tex]P=170+170[/tex]
[tex]P=340[/tex]
[tex]A=WL[/tex]
[tex]A=85^2[/tex]
[tex]A=7225[/tex]
There you have it. A rectangle with a smaller area with the same perimeter.
What does it show? The smaller the difference you get from width and length, the larger the area is.
