Sagot :
The molarity of Bromides ions in the chemist solution is 4.05 x 10^-3 M.
Molarity (M) refers to the amount of a substance in a given volume of solution and is defined as the moles of a solute per liters of a solution.
The equation for calculating the molarity of solution is given by:
Molarity of the solution = Mass of solute/ (Molar mass of solute x Volume of solution in L)
According to the given information,
Given mass of Vanadium (III) bromide = 0.12 g
Molar mass of Vanadium (III) bromide = 295.65 g/mol
Volume of solution = 300 mL or 0.3 L
Hence,
Molarity of the solution = 0.12/ (295.65 x 0.3) = 0.001352 or 1.3 x 10^-3 M
As the formula for Vanadium (III) bromide is VBr3. Hence, 1 mole of Vanadium(III) bromide produces 1 mole of V 3+ ions and 3 moles of Br -ions.
Molarity of bromide ions = 3 * 1.3 x 10^-3 M = 4.05 x 10^-3 M.
Note: The question is incomplete. The complete question probably is: A chemist prepares a solution of Vanadium (III) bromide (VBr) by measuring out 0.12 g of VBr into a 300 ml. volumetric flask and filling to the mark with distilled water. Calculate the molarity of Bromide ions in the chemist's solution. Be sure your answer is rounded to significant digits.
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