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A 1366 -ft equal tangent vertical curve i to be ued for joining a 5% grade line and a -8% grade line in that order. The PVI i at tation 5300 and the elevation of the PVI i 582. 97 ft. What i the value of r, the rate of change? Give your anwer to 2 decimal place

Sagot :

The value of r, the rate of change is r= 0.0095 % /ft. for equal tangent vertical curve

Length of Vertical curve (L)

L=1366ft

g1=+5%

g2=-8%

find rate of change of grade (r)

from the basics, we know

L= (g1-g2)/r

r = (g1-g2)/L = (5-(-8)) /1366ft

= 13 %/1366. ft

r= 0.0095 % /ft

Most vertical curves in highway design are equal-tangent curves, meaning that the horizontal distance from the curve's centre to its end is the same in both directions.

Distance in feet from the B.V.C. to the low or high point, where A is the algebraic sum of the intersecting grades +g and -ge (in percent/loo). H is the elevation that is created by adding the grade to the g along the line.

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