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a cylinder of mass 15.0 kg rolls without slipping on a horizontal surface. at a certain instant its center of mass has a speed of 8.0 m/s. (a) determine the translational kinetic energy of its center of mass.

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The translational kinetic energy of the cylinder of the mass of 15 kg which rolls with the speed of 8 m/s is 60 J

The mass of the cylinder = 15 kg

The speed of the cylinder = 8.0 m/s

The translational kinetic energy can be found using the formula,

                T.K.E = 1/2mv²

where T.K.E is the translational kinetic energy

                m is the mass of the cylinder

                v is the speed of the cylinder

Let us substitute the known values in the above equation, we get

              T.K.E = 1/2 x 15 x 8

                       = 120 / 2

                       = 60 J

Therefore, the translational kinetic energy of the cylinder is 60 J

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