Find the equation of a line perpendicular to y 7 = - 4/3x that pae through the point (-8, -1)

Sagot :

The equation of a line perpendicular to y 7 = - 4/3x that pass through the point (-8, -1) is 3x-4y=20 where x-intercept is 3 and y-intercept is -4.

What is an equation or line?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables.

What is equation of a straight line?

The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, often known as the y-intercept, and m is the gradient.

Given line ;

y 7 = - 4/3x

now comparing it with y=mx+c to find the value of m and we found;

m1=-4/3

now if two lines are perpendicular then,

m1.m2=-1

m2=3/4

now finding the equation of line passing through the point (-8, -1)

x1=-8

y1=-1

(y−y1)=m(x−x1)

Y+1=(3/4)(x+8)

Y+1=(3x/4)+(24/4)

Y=(3x/4)+(6)-1

Y=(3x+20)/4

4y=3x+20

rearrange;

3x-4y=20

this is our required value.

To learn more about equation of line visit:

https://brainly.com/question/11552995

#SPJ4