Sagot :
The points which satify the equation are solution of equations.
Substitute the points in the equation to check whether ordered pair are solution of equation or not.
[tex]\begin{gathered} 5\cdot\frac{-8}{5}+2\cdot0=-8 \\ -8+0=-8 \\ -8=-8 \end{gathered}[/tex]Point satify the equation. So ordered pair (-8/5,0) is solution of equation.
For second point,
[tex]\begin{gathered} 5\cdot0+2\cdot(-4)=-8 \\ 0-8=-8 \\ -8=-8 \end{gathered}[/tex]Point satify the equation. So ordered pair (0,-4) is soution of equation.
For third point;
[tex]\begin{gathered} 5\cdot(-4)+2\cdot0=-8 \\ -20+0=-8 \\ -20\ne-8 \end{gathered}[/tex]Point not satisfy the equation. So ordered pair (-4,0) is not the solution of equation.
For fourth point;
[tex]\begin{gathered} 5\cdot4+2\cdot(-14)=-8 \\ 20-28=-8 \\ -8=-8 \end{gathered}[/tex]Point satisfy the equation. So ordered pair (4,-14) is solution of equation.
For fourth point;
[tex]\begin{gathered} 5\cdot1+2(-2)=-8 \\ 5-4=-8 \\ 1\ne-8 \end{gathered}[/tex]Point not satisfy the equation. So ordered pair (1,-2) is not a solution of equation.
Answer:
A (-8/5,0)
B (0,-4)
D (4,-14)