first factor 3 out of 3-9i giving
[tex]3(1-3i)[/tex]then the original mutiplication would be
[tex](2i-4)\times3(-3i+1)[/tex]Now factor 2 out of 2i-4 giving
[tex]2(i-2)[/tex]Then the original multiplication would be
[tex]2(i-2)3(-3i+1)[/tex][tex]undefined[/tex]