Multiply both sides of the first equation by 4.
[tex]4x=16-20t[/tex]Multiply both sides of the second equation by 5.
[tex]5y=25+20t[/tex]Add the obtained equations.
[tex]4x+5y=41[/tex]Identify the y-intercept of the linear equation. Substitute 0 to the value of x and then solve for y.
[tex]\begin{gathered} 4(0)+5y=41 \\ 5y=41 \\ y=\frac{41}{5} \\ y=8.2 \end{gathered}[/tex]Thus, the y-intercept is (0,8.2).
Therefore, the graph whose y-intercept is (0,8.2) and whose x-intercept is (10.25,0) is the graph that represents the parametric equations.
