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smilesSmiles| An airplane took off at a constantangle of elevation. After the plane traveledfor 26 miles, it reached an altitude of 5miles, as amodeled below. To the nearesttenth of a degree, what was the angle ofelevation ?

SmilesSmiles An Airplane Took Off At A Constantangle Of Elevation After The Plane Traveledfor 26 Miles It Reached An Altitude Of 5miles As Amodeled Below To The class=

Sagot :

the angle of elevation is 11.1°

Explanation:

Using an illustration to identify the position of the angle:

θ = angle of elevation

Triangle is right angled:

opposite = side opposite the angle = 5 miles

hypotenuse = 26 miles

adjacent = ?

Since we know the values of opposite and the hypotenuse, we would use sine ratio (SOH) from SOHCAHTOA

[tex]\sin \theta=\text{ }\frac{5\text{ miles}}{26\text{ miles}}[/tex][tex]\begin{gathered} \sin \theta=\text{ 0.1923} \\ \text{Inverse of sine:} \\ \theta=\sin ^{-1}(0.1923) \end{gathered}[/tex][tex]\theta=\text{ 11.09}\degree[/tex]

To the enarest tenth, the angle of elevation is 11.1°

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