Sagot :
Given:
The mass of the truck is m1 = 3162 kg
The speed of the truck is v1i = 12 m/s in East
The mass of the parked car is m2 = 510 kg
The speed of car is v2i = 0 m/s
The speed of car after collision is v2f = 24 m/s in East
To find the speed of the truck after collision.
Explanation:
The final velocity of the truck will be
[tex]\begin{gathered} m1v1i+m2v2i=m1v1f+m2v2f \\ v1f\text{ =}\frac{m1v1i-m2v2f+m2v2i}{m1} \\ =\frac{3162\times12-510\times24+510\times0}{3162} \\ =8.129\text{ m/s} \end{gathered}[/tex]Thus, the speed of the truck after collision is 8.129 m/s