Given,
The initial pressure of the gas, P₁=P N/m²
The initial temperature of the gas, T₁=27 °C=300.15 K
The final temperature of the gas, T₂=77 °C=350.15 K
Let the new pressure of the gas be P₂
From Gay-Lussac's law,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]On substituting the known values,
[tex]\begin{gathered} \frac{P}{300.15}=\frac{P_2}{350.15} \\ \Rightarrow P_2=\frac{P}{300.15}\times350.15 \\ P_2=1.17P \end{gathered}[/tex]Therefore the new pressure will be 1.17 times the initial pressure, i.e., 1.17 P