[tex]y=4-3x\\
5x-y=22\\\\
5x-(4-3x)=22\\
5x-4+3x=22\\
8x=26\\
x=\dfrac{26}{8}=\dfrac{13}{4}\\\\
y=4-3\cdot\dfrac{13}{4}\\
y=4-\dfrac{39}{4}\\
y=\dfrac{16}{4}-\dfrac{39}{4}\\
y=-\dfrac{23}{4}\\\\
\boxed{(x,y)=\left(\dfrac{13}{4},-\dfrac{23}{4}\right)}[/tex]
