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If ABCD is dilated by a factor of 2, thecoordinate of B' would be:543С2B1-8 -7-6-5-4-3-2-1 012.34567891011-1A-2D-3B' = ([?], [ ]=4Cotor

If ABCD Is Dilated By A Factor Of 2 Thecoordinate Of B Would Be543С2B18 7654321 012345678910111A2D3B 4Cotor class=

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We have a figure ABCD that is dilated by a factor of 2.

We have to find the coordinate of the image point B'.

If the center of dilation is the origin (0,0) and the factor is k = 2, we can write the rule:

[tex](x,y)\longrightarrow(2x,2y)[/tex]

Then, for B(-1,1), we will get:

[tex]B=(-1,1)\longrightarrow B^{\prime}=(2\cdot(-1),2\cdot1)=(-2,2)[/tex]

Answer: B' = (-2,2)

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