SOLUTION:
[tex]\begin{gathered} \frac{2}{10}\text{ = }\frac{21}{b} \\ \\ b\text{ = }\frac{21\text{ X 10}}{2}\text{ = 105 f}eet \\ To\text{ find the length of the guy wire;} \\ \text{Hypotenuse}^2=Opposite^2+Adjacent^2 \\ l^2=105^2+(19+2)^2 \\ l^2\text{ = 11025 + 441} \\ l^2\text{ = 11466} \\ l\text{ = }\sqrt[]{11466} \\ l\text{ = 107.079} \\ l\text{ = 107 ( nearest foot)} \end{gathered}[/tex]
The length of the guy wire to the nearest foot is 107 feet.
