If an electron begins from rest and is accelerated by a field of 0.060 n/c, what is its speed when it collides with a metal atom?

Sagot :

The speed when it collides with a metal atom = 27.5m/s

What is kinetic energy?

A particle or item in motion has a form of energy called kinetic energy. When work, which entails the energy transfer is done on an object by applying a net force, that object acquires kinetic energy.

In the electric field, the electron loses potential energy while gaining kinetic energy. You may calculate the kinetic energy as

[tex]K=\frac{m_e v^2}{2}=e E d[/tex]

Here,

[tex]\text { } m_e=9.11 \cdot 10^{-31} \mathrm{~kg}[/tex] is the mass of the electron;

[tex]e=1.6 \cdot 10^{-19} C[/tex] is the charge of the electron;

E is the electric field;

The distance that an electron travels is called d;

When we solve for the electron's speed, we arrive at:

[tex]v=\sqrt{\frac{2 e E d}{m_e}}[/tex]

Calculate yields:

[tex]v=\sqrt{\frac{2 \cdot 1.6 \cdot 10^{-19} C \cdot 0.060 N / C \cdot 3.6 \cdot 10^{-8} \mathrm{~m}}{9.11 \cdot 10^{-31} \mathrm{~kg}}} \approx 27,5 \mathrm{~m} / \mathrm{s}[/tex]

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