Answer:
x= 0.
Step-by-step explanation:
1. Write the expression.
[tex]3cosx = 2+cosx[/tex]
2. Divide both sides by 3.
[tex]\frac{3cosx}{3} = \frac{2+cosx}{3} \\\\\frac{3cosx}{3} = \frac{2}{3} +\frac{cosx}{3} \\ \\cosx=\frac{2}{3} +\frac{cosx}{3}[/tex]
3. Subtract [tex]\frac{cosx}{3}[/tex] from both sides.
[tex]\frac{3cosx}{3} = \frac{2+cosx}{3} \\\\\frac{3cosx}{3} = \frac{2}{3} +\frac{cosx}{3} \\ \\cosx-\frac{cosx}{3}=\frac{2}{3} +\frac{cosx}{3}-\frac{cosx}{3}\\ \\\\cosx-\frac{cosx}{3}=\frac{2}{3}[/tex]
4. Simplify the fraction subtraction.
[tex]\frac{3cosx}{3} -\frac{cosx}{3}=\frac{2}{3}\\ \\\frac{3cosx-cosx}{3}=\frac{2}{3}[/tex]
5. Multiply both sides by 3.
[tex]3*\frac{3cosx-cosx}{3}=\frac{2}{3}*3\\ \\3cosx-cosx=\frac{6}{3}\\ \\3cosx-cosx=2[/tex]
6. Solve the subtraction.
[tex]2cosx=2[/tex]
7. Divide both sides by 2.
[tex]\frac{2cosx}{2} =\frac{2}{2} \\ \\cosx=1[/tex]
8. Take [tex]cos^{-1}[/tex] from both sides.
[tex]cos^{-1}(cosx) =cos^{-1}(1)\\ \\x=cos^{-1}(1)\\ \\x=0.[/tex]
