Sagot :
Answer:
35 small pies
Step-by-step explanation:
Framing system of linear equations and solving:
Let the number of large pies be 'l' and
The number of small pies be 's'.
Total pies sold = 45
⇒ l + s = 45 ------------(I)
l = 45 - s -------(II)
Cost of 45 pies = $120
Cost of 1 large pie = $5
Cost of 'l' large pies = 5*l = 5l
Cost of 1 small pie = $2
Cost of 's' small pie = 2*s = 2s
5l + 2s = 120 --------------(III)
Solving : substitution method
Substitute l = 45 -s in equation (III)
5*(45 - s) + 2s = 120
5*45 - 5*s + 2s = 120
225 - 5s + 2s = 120 {Combine like terms}
225 - 3s = 120
-3s = 120 - 225 {Subtract 225 from both sides}
-3s = -105
s = -105 ÷ (-3) {Divide both sides by (-3)}
s = 35
Substitute s = 35 in equation (II),
l = 45 - s
= 45 - 35
l = 10
[tex]\sf \boxed{\text{\bf 35 small pies were sold}}[/tex]