Q|C An object of mass m moves in simple harmonic motion with amplitude 12.0cm on a light spring. Its maximum acceleration is 108cm /s² . Regard m as a variable. (a) Find the period T of the object.

Sagot :

The time period T of the object is 2.09 seconds

Given

Mass of the object = m (considered as a variable).

The amplitude of the object = 12 cm.

Acceleration of the object = 108 cm2/s.

We have to find the Time period of the object= T (let’s assume)

We know from Harmonics

Acceleration of the object = (Amplitude of the object) * (Frequency of the object)2

⇒ 108 cm2/s = 12 cm * (ω)2

⇒ 108/12 = (ω)2

⇒ 9 = (ω)2

⇒ 3 = (ω)

Therefore, the frequency of the object = 3 Hz

Also

We know that

Frequency of the object = (2π) / (Time-Period of the object)

⇒ 3 Hz= (2π) / (Time-Period of the object)

Time-Period of the object = (2π)/3

⇒ T= 2.09 seconds

Hence Time Period of the object = 2.09 seconds

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