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1) Calculate the empirical formula for a chemical compound that gives the following analysis: 66.6 g titanium and 33.4 g oxygen.
a) Ti_2O_3
b) Ti_2O
c) TiO_3
d) Ti_2

2) The empirical formula for a compound shows the symbols of the elements with subscripts indicating what?

a) actual numbers of atoms in a molecule
b) number of moles of the compound in 100 g
c) smallest whole-number ratio of the atoms
d) atomic masses of each element

3) In the tin oxide laboratory activity, what was the color of the vapor emitted when the nitric acid was added to the tin?

a) orange-brown
b) pink
c) green
d) blue

4) What is the empirical formula for a compound that is 36.6 percent potassium, 33.2 percent chlorine, and 29.9 percent oxygen?

KClO_2
KClO_3
K_2Cl_2O
K_2Cl_2O_5

5) What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

P_3O_7
PO_3
P_2O_3
P_2O_5

Sagot :

Eduard22slyid

1. The empirical formula of the compound is Ti₂O₃

2. The correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. The correct answer to the question is: orange-brown (Option A)

4. The empirical formula of the compound is KClO₂

5. The empirical formula of the compound is P₂O₅

1. How to determine the empirical formula

  • Ti = 66.6 g
  • O = 33.4 g
  • Empirical formula =?

Divide by their molar mass

Ti = 66.6 / 48 = 1.3875

O = 33.4 / 16 = 2.0875

Divide by the smallest

Ti = 1.3875 / 1.3875 = 1

O = 2.0875 / 1.3875 = 3/2

Multiply by 2 to express in whole number

Ti = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Ti₂O₃

2. What is empirical formula?

This is the simplest formula of a compound which shows the smallest whole number ratio of the atoms present in the compound

With the above definition, we can conclude that the correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. What colour is shown when nitric acid is added?

In the tin oxide laboratory activity, the colour of the vapor emitted when nitric acid is added to the tin is: orange-brown

NOTE: This colour is visible when we carryout the practical experiment

Thus, the correct answer to the question is orange-brown (Option A)

4. How to determine the empirical formula

  • K = 36.6%
  • Cl = 33.2%
  • O = 29.9%
  • Empirical formula =?

Divide by their molar mass

K = 36.6 / 39 = 0.9385

Cl = 33.2 / 35.5 = 0.907

O = 29.9 / 16 = 1.8688

Divide by the smallest

K = 0.9385 / 0.907 = 1

Cl = 0.907 / 0.907 = 1

O = 1.8688 / 0.907 = 2

Thus, the empirical formula of the compound is KClO₂

5. How to determine the empirical formula

  • P = 43.6%
  • O = 56.4%
  • Empirical formula =?

Divide by their molar mass

P = 43.6 / 31 = 1.406

O = 56.4 / 16 = 3.525

Divide by the smallest

P = 1.406 / 1.406 = 1

O = 3.525 / 1.406 = 5/2

Multiply by 2 to express in whole number

P = 1 × 2 = 2

O = 5/2 × 2 = 5

Thus, the empirical formula of the compound is P₂O₅

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