Answer:
Option 2
Step-by-step explanation:
Since theta is in the third quadrant, the sine of theta is negative.
By the Pythagorean identity,
[tex]\sin \theta=-\frac{\sqrt{105}}{13}[/tex]
So, using the double angle formula for sine, we get that
[tex]\sin 2\theta=\frac{16\sqrt{105}}{169}[/tex]