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If p(x,3) Q(7,1) and pQ(15) unit find the possible value of x

Sagot :

Babylexi017id

Answer:

Step-by-step explanation: P(x 3), Q(7, -1) and PQ= 5 .

To Find :

The possible value of x.​

Solution :

We know, distance between two points in coordinate plane is given by :

Therefore, the possible value of x are 10 and 4.

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