Sagot :
Answer:
The answer is 455 ways.
Step-by-step explanation:
If adding only twelve, you must leave out three of the fifteen, and the number of ways is = 15! / (3! * 12!).
1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12∗13∗14∗15 over
(1∗2∗3)∗(1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12) =
13∗14∗15 over
(1∗2∗3)
27306 = 455
Answer: If all toppings are distinct, then you have C 4 15 combinations. If there are three distinct toppings, you have 3 ⋅ C 3 15 combinations (because we have C 3 15 choices for toppings and then 3 choices for which of those three toppings is doubled).
Step-by-step explanation: