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Michael took a drive down to the beach and drove at a pace of 45mph on the way there. The trip took him 3 hours. He drives the exact same route on the way back, but takes it slow so he can enjoy the sunset. If Henry's return trip took him 4 hours, how fast was he driving on his return?


Sagot :

Michael took the return trip at a velocity 33.75 miles per hour.

How fast did Michael drive in his return trip?

Let suppose that Michael drove in straight line road and at constant velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3     (1)

Second trip

v = s / 4       (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

To learn more on velocities: https://brainly.com/question/18084516

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