A 60-m long wire is coiled so that it makes a coil containing 140 square loops, one on top of each other. if the wire carries a current of 21 a, what is the magnetic dipole moment of the coil?

Sagot :

A 60-m long wire is coiled so that it makes a coil containing 140 square loops, one on top of each other. if the wire carries a current of 21 a, the magnetic dipole moment of the coil will be 0.24 Am2

Dipole moment = i * A

Area = ?

given total length of the wire = 60 m number of square loops = 140total length of the wire  =  n * ( circumference of one loop) circumference of one loop = total length of the wire   / n  = 60 / 140 = 0.429 m circumference of one loop  = 4 * (side of the square )                                  0.429 = 4 * a a = [tex]0.107 m[/tex]

Area of  loop = [tex]a^{2}[/tex]=  [tex](0.107)^{2}[/tex]  = [tex]0.01145 m^{2}[/tex]

Dipole moment = i * A  = 21 * 0.01145 = 0.24 A  [tex]m^{2}[/tex]

To learn more about Dipole moment  here

https://brainly.com/question/14058533

#SPJ4