A newspaper article reported that people spend a mean of 7 hours per day watching TV, with a standard deviation of 1.8 hours. A psychologist would like to conduct interviews with the 5% of the population who spend the most time watching TV. She assumes that the daily time people spend watching TV is normally distributed. At least how many hours of daily TV watching are necessary for a person to be eligible for the interview? Carry your intermediate

Sagot :

According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

According to the statement

we have given that the mean of 7 hours per day watching TV, and a standard deviation of 1.8 hours.

And we have to find that the At least how many hours of daily TV watching are necessary for a person to be eligible for the interview.

So, For this purpose,

The confidence interval is is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level.

Let us Assume x is the amount of hours that 5% of the persons exceeds.

Then P(z<(x-7)/1.8) = 0.95

From a standard normal table, we know that:

(x-7)/1.8 = 1.6449

x-7 = 2.9607

x = 9.9607

So, According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

Learn more about confidence interval here

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