A 21. 2-l sample of nitrogen at 3. 65 atm and 22°c is simultaneously expanded to 62. 6 l and heated to 34°c. what is the new pressure of the gas?
a. a. 349 atm
b. 235 atm
c. 1. 19 atm
d. 1. 29 atm
e. 1. 91 atm


Sagot :

Then the new pressure of the sample of nitrogen is  1.28 atm

So, option D is correct one.

Calculation,

Formula used : [tex]P_{1} V_{1} /T_{1} =P_{2} V_{2}/T_{2}[/tex]             (i)

Where , P is pressure and V is the volume

Given data,

[tex]P_{1}[/tex] = 3. 65 atm

[tex]V_{1}[/tex] = 21. 2 L

[tex]P_{2}[/tex] =

[tex]V_{2}[/tex] = 62. 6 L

[tex]T_{1}[/tex] = 22°C = 22+273 = 295 K

[tex]T_{2}[/tex] = 34°C = 34 +273 = 307 K

Putting the value of all data given in equation (i) we get,

3. 65 atm ×  21. 2 L/295 K = [tex]P_{2}[/tex] ×  62. 6 L / 307 K

[tex]P_{2}[/tex] = 3. 65 atm × 21. 2 L × 307 K/295 K × 62. 6 L = 1.28 atm

Then the new pressure the sample of nitrogen is  1.28 atm

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