Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units

Sagot :

The δs∘rxn  for the reaction [tex]2NO(g) + O_{2}[/tex] → [tex]2NO_{2} (g)[/tex] will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit [tex]JK^{-1} mol^{-1}[/tex].

Entropy of the reaction can be calculated by the reaction.

Δ[tex]S^{0} rxn[/tex] = 2 mol × [tex]S^{0} (NO_{2} (g) - 2 mol[/tex] × [tex]S^{0} NO (g)[/tex] - 1 mol × [tex]S^{0} (O_{2} )[/tex]

Δ[tex]S^{0} rxn[/tex]  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

Δ[tex]S^{0} rxn[/tex]  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction [tex]2NO(g) + O_{2}[/tex] → [tex]2NO_{2} (g)[/tex] will be -146 J/K.

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