Sagot :
The pH of the solution is 9.14
For ammonia:
To calculate the amount of hydrogen gas collected, we use the equation given by ideal gas which follows:
PV = nRT
P= Pressure of the gas = 735 torr
V= volume of the gas = 7.70 l
T= Temperature of the gas= 22°C (22+273K) = 295K
R= Gas constant= 62.364 L torr/mol/K
n = number of moles of ammonia = ?
By substituting the values in the above equation, we get:
735×7.70 = n × 62.364 × 295
5659.5 = n × 18397.38
n= 5659.5/18397.38
n= 0.3076
For hydrochloric acid:
To calculate the number of moles for given molarity, we use the equation:
Molarity of the solution = [tex]\frac{moles of solute}{volume of solution}[/tex]
Molarity of hydrochloric acid = 0.400 M
Volume of solution = 0.250 L
Putting values in above equation, we get:
0.400= moles of solute/0.250
moles of hydrochloric acid = 0.1 mol
The chemical reaction for ethylamine and HCl follows the equation:
NH3+HCl---> NH4Cl
Initial: 0.316 0.18
Final: 0.136 - 0.18
volume of the solution = 0.250 l
To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:
pOH = pKb + log([tex]\frac{salt}{base}[/tex])
pOH = pKb + log([tex]\frac{NH4Cl}{NH3}[/tex])
it is given:
pKb = negative logarithm of base dissociation constant of ammonia =
-log(1.8 × [tex]10^{-5}[/tex]) = 4.74
[NH4Cl] = 0.18/0.450
[NH3] = 0.136/0.450
On substituting the values we get,
pOH= 4.74 + log ([tex]\frac{0.18/0.250}{0.136/0.250}[/tex])
pOH = 4.74 + 0.12
pOH= 4.86
pH + pOH= 14
pH= 14-pOH
= 14-4.86
pH = 9.14
pH of the solution = 9.14
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