The length of rectangle is 25 feet and the width of rectangle is 135 feet.
According to the question,
The perimeter of a rectangle is 320 feet. The length and width if the length is an odd integer and the width is 5 times the next consecutive odd integer.
Odd integers that follow each other and they differ by 2. If x is an odd integer, then x + 2, x + 4 and x + 6 are consecutive odd integers. The perimeter of a rectangle is 320 feet. Let the length of a rectangle is x. The next consecutive odd integer is x+2.width = 5(x+2)
=5x+10.
Let, Length - l:Width - w; l = 5w and the perimeter of a rectangle is 320 feet. Formula for perimeter of rectangle is 2(Length + Breadth). Perimeter of a rectangle is the sum of the length of all sides of the rectangle. The perimeter of a rectangle formula is,
P = 2(l + b)
In words, it is equal to the sum of two times the length and two times the breadth of the rectangle. Perimeter for any figure is defined as the length of its boundary.
2(length + width) = 320
Length+ width=160
x+5x+10=160
6x=150
x=25
Length = 25 feet
width = 5(25+2)=135 feet.
Hence, the length of rectangle is 25 feet and the width of rectangle is 135 feet..
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