The solutions for the given system are (3,2), (3,-2), (-3,2) and (-3,-2).
The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.
The solution of these equations represents the points at which the parabolas intersect.
2x²+8y²=50 (1)
x² + y²= 13 (2)
Multiplying the equation 2 by -2, you have:
2x²+8y²=50 (1)
-2x² -2 y²= -26(2)
Sum both equations, you have: 6y²= 24. Now, you can find y.
6y²= 24
y²=4
y=±2
If y=2, from equation 2, you have
x² + y²= 13
x² + 2²= 13
x² + 4= 13
x² =13-4
x² =9
x=±3
Read more about the solution to the system of equations here:
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