By the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.
Herein we have a quadratic equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the quadratic formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.
To learn more on quadratic equations: https://brainly.com/question/1863222
#SPJ1