Find the solution to the system of equations: x 3y = 7 and 2x 4y = 8 1. isolate x in the first equation: 2. substitute the value for x into the second equation: 3. solve for y: 4. substitute y into either original equation: 5. write the solution as an ordered pair:

Two or more equations using the same variable are referred to mathematically as a "system of linear equations." These equations' solutions serve as a representation of the intersection of the lines.

According to the given information:

Two equations are presented here:

1) x + 3y = 7

2) 2x + 4y = 8

First, in the first equation, we want to isolate x:

x + 3y = 7

x = 7 -3y

In order to create an equation that depends just on the variable y, we must now b) swap it out in the second equation.

2x + 4y = 8

2(7 - 3y) + 4y = 8

The value of y is now determined by solving this equation in step (c).

14 - 6y + 4y = 8

14 - 2y = 8

-2y = 8 - 14 = -6

y= 6/2= 3

d) With the value of y now available, we can change the equation we obtained in step a) by substituting it.

x = 7 - 3y

x = 7 - 3*3 = 7 - 9 = -2

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I understand that the question you are looking for is:

Find the solution to the system of equations, x + 3y = 7 and 2x + 4y = 8.

1. Isolate x in the first equation: x = 7 − 3y

2. Substitute the value for x into the second equation: 2(7 − 3y) + 4y = 8

3. Solve for y:

14 − 6y + 4y = 8

14 − 2y = 8

−2y = −6

y = 3

4. Substitute y into either original equation: x = 7 − 3(3)

5. Write the solution as an ordered pair: