a. Expressing y in terms of x, y = 20/(x + 3)
b. When x = 5, the value of y is 2.5
The question has to do with inverse variation.
Inverse variation is variation in which one quantity varies inversely as the other.
Given that y is inversely as x + 3 and that y = 4 when x = 2.
Since y varies inversely as x + 3, we have
y ∝ 1/(x + 3)
y = k/(x + 3)
When y = 4, x = 3. So
y = k/(x + 3)
4 = k/(2 + 3)
4 = k/5
k = 4 × 5
k = 20
So, y = k/(x + 3)
y = 20/(x + 3)
So, expressing y in terms of x, y = 20/(x + 3)
Since y = 20/(x + 3)
Substituting x = 5 into the equation, we have
y = 20/(x + 3)
y = 20/(5 + 3)
y = 20/8
y = 5/2
y = 2.5
So, when x = 5, the value of y is 2.5
Learn more about inverse variation here:
https://brainly.com/question/27887206
#SPJ1
