The drug will decay to 82% of the initial dosage after 7.18 hours.
Finding the Decay constant(λ):
λ = 0.693 / (half-life)
we are given that the half-life is 47 hours
λ = 0.693 / (47)
λ = 0.01925 /hour
Time is taken for 82% decay:
Since decay is first-order, we will use the formula:
[tex]t = \frac{2.303}{0.0192} log\frac{100}{82}[/tex]
Final amount = 100*82/100 = 82 mg
Replacing the values in the equation:
t = 2.303/ 0.0192 x 0.06
t = 7.18 hours
Therefore, the drug will decay to 82% of the initial dosage after 7.18 hours.
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