[Will Mark Brainliest]
Make tables to find the solution to 8x = 2x + 2. Take the integer values of x between -3 and 3.


Sagot :

Answer:

i'm not realy sure what you mean by a table

8x=2x+2

subtract 2x from each side

6x=2

divide by 6

x=1/3

Hope This Helps!!!

Step-by-step explanation:

So if you want to make a table to find the solution, you'll need 3 columns, one will be the value of x, the other two will be the value of the equation (left and right) and then you'll need to look where the two equations are equal, and the solution is whatever the x-value is. It'll look something like this:

[tex]x\ \ \ \ |\ 2x+2\ |8x\\-3\ \| -4\ \ \ \ \ | -24\\-2\ \| -2\ \ \ \ \ |-16\\-1\ \| 0\ \ \ \ \ \ \ \ \ | -8\\0\ \ \ \ \|2\ \ \ \ \ \ \ \ \ | 0 \\1\ \ \ \ \| 4\ \ \ \ \ \ \ \ \ | 8\\2\ \ \ \ \|6\ \ \ \ \ \ \ \ \ | 16\\3\ \ \ \ \|8\ \ \ \ \ \ \ \ \ | 24[/tex]  

As you can see, none of rows (the two right most columns with the equations) are ever equal, on the same row. This is because the solution is not an integer. If you solve it algebraically. You'll get this:

Original equation

8x = 2x+2

Subtract 2x from both sieds

6x = 2

Divide both sides by 6

x = 2/6

Simplify the fraction

x=1/6