Find the length of the short leg on the following right triangle.

Find The Length Of The Short Leg On The Following Right Triangle class=

Sagot :

60+90+ angle U = 180 {sum of angle of triangle}

or, 150+ U= 180

or, angle U = 30°

From here we got that ,

angle U is smallest.

We know that, side opposite to the shortest angle is shortest side. So , short leg is side PM

In right angled triangle PMU,

hypotenuse(h) = 10

angle theta = 60°

perpendicular (PM)= ?

NOW,

sin theta = Perpendicular/ hypotenuse

or, sin 60° = P/10

[tex] \\or \frac{ \sqrt{3} }{2} = p \div 10[/tex]

[tex] or\frac{10 \sqrt{3} }{2} = p[/tex]

[tex]or \: 5 \sqrt{3 } = p[/tex]

Therefore,

[tex]short \: leg = 5 \sqrt{3} [/tex]